Question 344008
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Let *[tex \Large x] represent the denominator of the original fraction.  Then the original fraction must be *[tex \Large \frac{x\ -\ 3}{x}].  And the modified fraction must be *[tex \Large \frac{3x\ -\ 9}{x\ +\ 7}].  So we can write:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{3x\ -\ 9}{x\ +\ 7}\ =\ \frac{3}{2}]


Divide both sides by 3, cross-multiply, collect like terms, and solve for *[tex \Large x].


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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