Question 343904
{{{dhe=5x-10 }}}
{{{fhe=2x+35}}}
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{{{dhe=fhe}}} <--- Since {{{he}}} is the bisector of {{{dhf}}}.
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{{{5x-10=2x+35}}}
{{{3x=45}}}
{{{highlight(x=15)}}}
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{{{dhe=fhe=5(15)-10=75-10=highlight_green(65)}}}degrees