Question 343910
{{{2x+5y=8}}}
{{{5y=-2x+8}}}
{{{y=-(2/5)x+8/5}}}
The slope of this line is {{{m=-2/5}}}
Perpendicular lines have slopes that are negative reciprocals.
{{{m1*m2=-1}}}
{{{-(2/5)*m2=-1}}}
{{{m2=5/2}}}
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{{{y=(5/2)x+b}}}
Use the point to solve for {{{b}}}.
{{{-5=(5/2)(20)+b}}}
{{{b+50=-5}}}
{{{b=-55}}}
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{{{highlight(y=(5/2)x-55)}}}
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{{{drawing(300,300,-5,30,-30,5,grid(1),circle(20,-5,0.5),graph(300,300,-5,30,-30,5,-(2/5)x+8/5,(5/2)x-55))}}}