Question 343800
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8 ways to pick the hundreds digit times 8 ways to pick the tens digit times 8 ways to pick the ones digit is 512


Then you have the same 512 for the negative numbers


So 1024 but you have to subtract one because of counting 0 twice  hence 1023


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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