Question 343682
If the function is {{{f(x)=2^(x+2)}}}, then (0,4) and (1,8) are on the graph. The point (-1,1) is NOT on the graph, but the point (-1,2) is on the graph.



The graph looks like 


{{{ drawing(500, 500, -10, 10, -10, 10,
 graph( 500, 500, -10, 10, -10, 10,2^(x+2))

)}}}



Now use the graph above to get



Domain: The set of all real numbers.


Range: {{{y>0}}}


Horizontal Asymptote: {{{y=0}}}



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