Question 343592
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The sum of a series of numbers is given by the first plus the last times the number of numbers divided by 2.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{(a\ +\ l)n}{2}]


The first multiple of 3 is 3, the 600th multiple of 3 is 1800, and there are 600 numbers.


The first odd number is 1, the 600th odd number is 2 X 600 - 1 = 1199, and there are 600 numbers.


You want:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \frac{(3\ +\ 1800)(600)}{2}\ -\ \frac{(1\ +\ 1199)(600)}{2}\ =\ (300)(1803\ -\ 1200)\ =\ 300\ \times\ 603]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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