Question 343489
You mean like this?
{{{sqrt(4x)-x+3=0}}}
{{{sqrt(4x)=x-3}}}
{{{4x=(x-3)^2}}}
{{{4x=x^2-6x+9}}}
{{{x^2-10x+9=0}}}
{{{(x-1)(x-9)=0}}}
Two solutions:
{{{x-1=0}}}
{{{highlight(x=1)}}}
.
.
.
{{{x-9=0}}}
{{{highlight(x=9)}}}