Question 4953
Solve:
  {{{sqrt(2x-3)}}}+x=3  Subtract x from both sides.
{{{sqrt(2x-3)}}}=3-x    Square both sides.
2x-3 = 9-6x+x^2   Simplify.
x^2-8x+12 = 0  Solve by factoring.
(x-2)(x-6) = 0  Apply the zero poducts principle.
x-2 = 0; x = 2
x-6 = 0; x = 6

The roots are: x = 2,  x = 6