Question 343425
NOTE: QUESTION STATES "CONSECUTIVE EVEN INTEGERS"
LET E[1] REPRESENT THE FIRST OF THE THREE "CONSECUTIVE EVEN INTEGERS"

THE QUESTION STATES THE FOLLOWING TO BE TRUE:
{{{E[1]+(E[1]+2)+(E[1]+4)=2(E[1])+48}}} 

SOLVE:
COMBINE
{{{3E[1] +6 = 2(E[1])+48}}} 

SUBTACT {{{2E[1]}}} FROM BOTH SIDES OF THE EQUATION

{{{E[1] +6 = 48}}} 

SUBTACT 6 FROM BOTH SIDES OF THE EQUATION

{{{E[1]= 42}}} CONSECUTIVE EVEN INTEGERS ARE 42,44,46
CHECK YOUR ANSWER!! 42+44+46 = 132 = 84 +48