Question 343440
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Let *[tex \Large n] represent the number of nickels.


Let *[tex \Large d] represent the number of dimes.


Let *[tex \Large q] represent the number of quarters.


And we know:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ n\ +\ d\ +\ q\ =\ 60]


But we also know that


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ q\ =\ n\ -\ 5]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ d\ =\ q\ +\ 10]


but that means:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ d\ =\ (n\ -\ 5)\ +\ 10\ =\ n\ +\ 5]


Then substituting:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ n\ +\ (n\ +\ 5)\ +\ (n\ -\ 5)\ =\ 60]


Solve for *[tex \Large n] and then the other two values follow directly.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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