Question 343432
<font face="Garamond" size="+2">


Let *[tex \Large x] represent the "some number."  Then twice some number must be *[tex \Large 2x].  Then the sum of 3 and twice some number must be *[tex \Large 3\ +\ 2x].  Then 5 times the sum...must be *[tex \Large 5\(3\ +\ 2x)].  Finally, "is" means equals so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5\(3\ +\ 2x) = 70]


Solve for *[tex \Large x].


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
<img src="http://www.evolvefish.com/fish/media/E-FlyingSpaghettiEmblem.gif">
</font>