Question 343286
x+5=y_2x+3y=80

Since 5 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 5 from both sides.
x=-5+y_2x+3y=80

Move all terms not containing x to the right-hand side of the equation.
x=y-5_2x+3y=80

Replace all occurrences of x with the solution found by solving the last equation for x.  In this case, the value substituted is y-5.
x=y-5_2(y-5)+3y=80

Multiply 2 by each term inside the parentheses.
x=y-5_2y-10+3y=80

Since 2y and 3y are like terms, add 3y to 2y to get 5y.
x=y-5_5y-10=80

Since -10 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 10 to both sides.
x=y-5_5y=10+80

Add 80 to 10 to get 90.
x=y-5_5y=90

Divide each term in the equation by 5.
x=y-5_(5y)/(5)=(90)/(5)

Simplify the left-hand side of the equation by canceling the common factors.
x=y-5_y=(90)/(5)

Simplify the right-hand side of the equation by simplifying each term.
x=y-5_y=18

Replace all occurrences of y with the solution found by solving the last equation for y.  In this case, the value substituted is 18.
x=(18)-5_y=18

Remove the parentheses around the expression 18.
x=18-5_y=18

Subtract 5 from 18 to get 13.
x=13_y=18

This is the solution to the system of equations.
x=13_y=18