Question 343158
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Let *[tex \Large n] represent the number of nickels.


Let *[tex \Large d] represent the number of dimes.


Let *[tex \Large q] represent the number of quarters.


Let *[tex \Large c] represent the total number of coins.


Then


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ n\ +\ d\ +\ q\ =\ c]


But we are given that *[tex \Large q\ =\ 2n], so substitute:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ n\ +\ d\ +\ 2n\ =\ c]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 3n\ +\ d\ =\ c]


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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