Question 343039
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Just substitute the values and do the arithmetic:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -k^2\ -\ (3k\ -\ 5n)\ +\ 4n] 


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ -(-1)^2\ -\ (3(-1)\ -\ 5(-2))\ +\ 4(-2)]


You can do your own arithmetic.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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