Question 4953
{{{sqrt(2x-3)+x=3}}}

Subtract x from both sides and rewrite this equation as 
{{{sqrt(2x-3)=3-x}}}

square both sides:
{{{(sqrt(2x-3))^2=(3-x)^2}}}
{{{2x-3=9-6x+x^2}}}
subtract 2x and add 3 to both sides to get
{{{0=x^2-8x+12}}}
Factor:
(x-6)(x-2)=0
x=6,2