Question 342976
{{{(68f^(5)g^(-3)) /(4f^(-3)g^(6))=(68/4)f^(5-(-3))g^(-3-6)}}}
{{{(68f^(5)g^(-3)) /(4f^(-3)g^(6))=17f^(8)g^(-9)}}}
{{{(68f^(5)g^(-3)) /(4f^(-3)g^(6))=(17f^8)/(g^(9))}}}