Question 342939
{{{p= 2(l+w)=40}}}......eqn 1
{{{w= l/2 -1}}}
substitutiong w in eqn 1
{{{2(l+ l/2 -1) =40}}}
{{{2l + l -2 = 40}}}
{{{3l=40+2}}}
{{{3l/3=42/3}}}
{{{l=14}}} ft
so {{{w= l/2-1}}}={{{14/2-1}}}={{{6}}}ft