Question 342932
The expression 3x(a-3)-5(3-a) becomes 3x(a-3)-5(3-a) after using the distributive rule.



20x^2 - 7x - 6 factors out to be (5x+2)(4x-3).  To factor this one, I used the GROUPING METHOD.



4x^4 + 12x^3- 28x^2 factors out to be 4x^2(x^2 + 3x - 7).  To factor this one, I needed to do some extra substitutions in terms of letting y = x^2.


Done!