Question 4954
{{{2x^3-x^2-18x+9=0}}}

Factor by grouping:

{{{x^2(2x-1)-9(2x-1)=0}}}
{{{(2x-1)(x^2-9)=0}}}

{{{(2x-1)(x-3)(x+3)=0}}}

So either 2x-1 = 0 OR x-3=0 or x+3=0

x=1/2,3,-3