Question 342838
Jack is twice as old as Lacy. 
J = 2L
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In 3 years the sum of their ages will be 54. 
(J+3)+(L+3) = 54
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How old are they now?
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Substitute for J and solve for "L":
(2L+3)+(L+3) = 54
3L + 6 = 54
3L = 48
L = 16 (Lacy's age now)
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Since J=2L, J = 32 (Jack's age now)
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Cheers,
Stan H.