<PRE><B>Question 342704</B>
{{{1/(3x+18)-1/(2x+12)=1/(x^2+6x)}}}
Find a common denominato, {{{x(x+6)=x^2+6x}}}
{{{(1/3)(x/(x(x+6)))-(1/2)(x/(x(x+6)))=1/(x(x+6))}}}
Multiply both sides by {{{6}}},
{{{(2x)/(x(x+6))-(3x)/(x(x+6))=6/(x(x+6))}}}
{{{-(x)/(x(x+6))=6/(x(x+6))}}}
{{{highlight(x=-6)}}}
The only issue is that {{{x=-6}}} is not allowed as a solution since it would cause a division by zero.
There is no solution.
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