Question 39005
Okay from
log(6)5 = log(6)(2x+1) - log(6)(3x+4)
we combine to get
log(6)5 = log(6)[(2x+1) / (3x+4)] and then eliminating logs we have
(2x+1) / (3x+4) = 5
15x + 20 = 2x + 1
13x = -19
x = -19/13
but since that would make log(6)(2x+1) the log of a negative, the answer is NO SOLUTION...poor problem construction actually...