<PRE><B>Question 342546</B>
The question gives you one of the answers.

On the return trip, Patrick&#39;s speed was 10 mph.

GOING:

rate = x

time = 3

Distance = x(3)

Returning:

rate = 10

time = 4

Distance = 40 miles


The distance going and returning = 40 miles.

Let r = speed on the going trip

40 = 3r

40/3 = r

13.33 = r

The speed on the going trip was 13.33 mph.





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