Question 341639
{{{ax+b > c(x+d)}}}
{{{ax+b > cx+cd}}}
{{{ax-cx>cd-b}}}
{{{x(a-c)>cd-b}}}
If {{{(a-c)>0}}}, then {{{x>(cd-b)/(a-c)}}}
If {{{(a-c)<0}}}, then {{{x<(cd-b)/(a-c)}}}
If {{{(a-c)=0}}}, and {{{b>cd}}}, then the solution is all {{{x}}}.
If {{{(a-c)=0}}}, and {{{b<cd}}}, then there is no solution.