Question 342356
Total number of coins,
1.{{{N+D=70}}}
Total value of the coins,
{{{5N+10D=555}}}
2.{{{N+2D=111}}}
Subtract eq. 1 from eq. 2,
{{{N+2D-N-D=111-70}}}
{{{highlight(D=41)}}}
Then from eq. 1,
{{{N+41=70}}}
{{{highlight(N=29)}}}
There are {{{29}}} nickels and {{{41}}} dimes.