Question 342334
{{{L=6+2W}}}
The perimeter of a rectangle is,
{{{P=2L+2W=540}}}
{{{L+W=270}}}
Substituting from the first equation,
{{{6+2W+W=270}}}
{{{6+3W=270}}}
{{{3W=264}}}
{{{highlight(W=88)}}} yds.
Then from the first equation,
{{{L=6+2(88)}}}
{{{L=6+176}}}
{{{highlight(L=182)}}} yds.