Question 342429
I'll do the first two.
You finish it.
{{{n=1}}}, {{{2n^2+3n=2(1)^2+3(1)=2(1)+3=2+3=5}}}
{{{n=2}}}, {{{2n^2+3n=2(2)^2+3(2)=2(4)+6=8+6=14}}}
Do it the same way.