Question 342420
Three points that form the vertices of a triangle are: (-4,3), (-7, -1), (3, -2) 
Use the distance formula to determine if the triangle is a right triangle. 
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The distance is:
{{{s = sqrt(diffy^2 + diffx^2)}}} diffy = difference of y's
Subtract, then square.
For (-4,3) and (-7,-1):
{{{s = sqrt(4^2 + 3^2) = 5}}}
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Can you finish it?