Question 342416
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To determine the average of *[tex \Large n] numbers, you add up the numbers and divide by *[tex \Large n].  In your case you have an average of 88 for 5 scores, which means that the total of the scores must be *[tex \Large 5\ \times\ 88\ =\ 440].


In order to determine the lowest possible score that he could have obtained on any of his tests, you would have to know the maximum possible score that could have been obtained on any of the exams.  (440 minus 4 times the maximum score = the lowest possible score to obtain an 88 average).  Since you didn't bother to share that essential piece of information, there is no way to tell what the lowest score could be.  I can't even tell if zero is an appropriate lower bound because you didn't share whether or not negative scores are possible.


Present the WHOLE problem and someone here will see what we can do.  If what you presented was the whole problem as it was presented to you, go back to your instructor/teacher/professor and ask for the rest of the problem.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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