Question 342367
since the drawing is with replacement 
the probability of selecting a red is constant.
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Let prob(red)=p=2/5 , let prob(white)=1-p=3/5
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If X represent number of draws until the first success, ie selecting the first red,
then the pdf of X implies that there will be X-1 failures and the last one will be a success

{{{P(X=x)=(1-p)^(x-1)p}}}={{{(3/5)^(x-1)(2/5)}}} for x>0
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this is the geometric probability distribution, since is sequence increases geometrically