Question 264616
Let T=weight of the tetrahedron
Let C=weight of the cube
Let S=weight of the sphere
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given
scale 1: T+C+S=23
scale 2: 2C+2S=22  ---> C+S=11  divide both sides by 2
scale 3: 2T+S=26
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substitute C+S=11 from scale 2 into expression from scale 1
T+(C+S)=T+11=23
T=23-11=12
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substitute T=12 into expression from scale 3
2T+S=2*12+S=26
S=26-24=2
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substitute T=12, S=2 into expression in scale 1
T+C+S=12+C+2=23
C=23-14=9
==
answer T=12, S=2, C=9