Question 342211
{{{-2t^2=-8}}}
Put the equation in standard form, {{{ax^2+bx+c=0}}}
{{{-2t^2+8=0}}}
Now compare,
The coefficient of the {{{t^2}}} term :{{{a=-2}}}
The coefficient of the {{{t}}} term :{{{b=0}}}
The constant terme :{{{c=8}}}