Question 342228
Use the common denominator, {{{x^2-1=(x-1)(x+1)}}}
{{{10/(x^(2)-1)-5/(x-1)=3/(x+1)}}}
{{{10/(x^2-1)-(5(x+1))/((x-1)(x+1))=(3(x-1))/((x-1)(x+1))}}}
{{{(10-5(x+1)-3(x-1))/((x-1)(x+1))=0}}}
{{{(10-5x-5-3x+3)/((x-1)(x+1))=0}}}
{{{(-8x+8)/((x-1)(x+1))=0}}}
{{{(-8(x-1))/((x-1)(x+1))=0}}}
{{{(-8)/(x+1)=0}}}
No solution.