Question 342227
If newborn baby averge length is 20 inches and the standard deviation is 1inch 
what is`probabilty new born over 22inches long
z(22)=(22-20)/1 = 2
P(x > 22) = P(z > 2) = normalcdf(2,100) = 0.0228
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what is probability between 18 and 22 inchs long
z(18) = (18-20)/1 = -2
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P(18 < x < 22) = P(-2< z < 2) = normalcdf(-2,2) = 0.9545
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Cheers,
Stan H.