Question 342187
Assume I have a stopwatch which I will start 
when I leave house 12 min after movers.
My equation of motion is {{{d[1] = 65t}}}
The equation for the movers is {{{d[2] = 50*(t + 12/60)}}}
Note that at {{{t=0}}} when the stopwatch starts
{{{d=0}}} for me, and {{{d=10}}} for movers
To find the time on stopwatch when I pass the movers,
set my {{{d[1]}}} equal to their {{{d[2]}}}
{{{65t = 50*(t + 1/5)}}}
{{{65t = 50t + 10}}}
{{{15t = 10}}}
{{{t = 2/3}}} hr
{{{t = (2/3)*60}}} min
{{{t = 40}}} min (time on stopwatch when I pass movers)
Here's a plot of the 2 equations:
{{{ graph( 500, 500, -1, 2, -10, 100, 65x, 50x + 10) }}}
When {{{d[1] = 86}}},
 {{{t = 86/65}}}
{{{t = 1.323}}} hr
and {{{d[2] = 50*(1.323 + .2)}}}
{{{d[2] = 76.15}}} mi
{{{86 - 76.15 = 9.85}}} mi
This is how far behind the mover is when I reach house