Question 341833
Call the consecutive odd integers
{{{n}}},{{{n + 2}}}, {{{n+4}}}
given:
{{{n + n+ 4 = 5*(n + 2) - 51}}}
{{{2n + 4 = 5n + 10 - 51}}}
{{{5n - 2n = 4 - 10 + 51}}}
{{{3n = 45}}}
{{{n = 15}}}
{{{n + 2 = 17}}}
{{{n + 4 = 19}}}
The numbers are 15, 17, and 19
check answer:
{{{n + n+ 4 = 5*(n + 2) - 51}}}
{{{15 + 19 = 5*17 - 51}}}
{{{34 = 85 - 51}}}
{{{34 = 34}}}
OK