Question 341649
log2 (x + 4) = 3 + log2 (x - 5)
:
Subtract log2 (x-5) from both sides
log2 (x + 4) - log2 (x - 5) = 3
same as
log2({{{(x+4)/(x-5)}}}) = 3
The exponent equiv
{{{2^3}}} = {{{(x+4)/(x-5)}}}
8 = {{{(x+4)/(x-5)}}}
:
8(x-5) = x + 4
8x - 40 = x + 4
8x - x = 4 + 40
7x = 44
x = {{{44/7}}}