Question 341698
1.{{{y=x^2+4x-3}}}
2.{{{y=5x+3}}}
{{{5x+3=x^2+4x-3}}}
{{{x^2-x-6=0}}}
{{{(x-3)(x+2)=0}}}
Two solutions:
{{{x-3=0}}}
{{{x=3}}}
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{{{x+2=0}}}
{{{x=-2}}}
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Now that you have the x values, use either equation to solve for the corresponding y-values. 
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Graphical verification
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{{{drawing(300,300,-10,10,-8,20,grid(1),circle(-2,-7,0.3),circle(3,18,0.3),graph(300,300,-10,10,-8,20,x^2+4x-3,5x+3))}}}