Question 341705

{{{7x+4y=16}}} Start with the given equation.



{{{4y=16-7x}}} Subtract {{{7x}}} from both sides.



{{{4y=-7x+16}}} Rearrange the terms.



{{{y=(-7x+16)/(4)}}} Divide both sides by {{{4}}} to isolate y.



{{{y=((-7)/(4))x+(16)/(4)}}} Break up the fraction.



{{{y=-(7/4)x+4}}} Reduce.



So the equation {{{y=-(7/4)x+4}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=-7/4}}} and the y-intercept is {{{b=4}}} note: the y-intercept is the point *[Tex \LARGE \left(0,4\right)]



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