Question 341617
Let's work backwards.
Find the ones that are.
{{{ 1^2=1}}}
{{{2^2=4}}}
{{{3^2=9}}}
{{{4^2=16}}}
{{{5^2=25}}}
{{{6^2=36}}}
{{{7^2=49}}}
{{{8^2=64}}}
{{{9^2=81}}}
{{{10^2=100}}}
That makes {{{10}}}. 
From {{{1}}} to {{{100}}}, there are {{{100}}} numbers.
So {{{100-10=90}}} of them are not squares of an integer.