Question 4924
{{{V = (1/3) *pi * r^2 *h }}}, where base = {{{pi* r^2 = 27}}} and height = 6
{{{V = (1/3) * 27 * 6}}}
{{{ V = 54 }}} cubic feet.


Notice that  1 cubic yard = 27 cubic feet, which equals 1 load.


Since V = 54, that would be 2 cubic yards or two loads.


R^2 at SCC