Question 341538
A coffee shop owner mixes two types of coffees to make a specialty blend. Alone, the coffees sell for $7.50 and $10.00 per pound. How many pounds of each type of coffee should be used to make 15 pounds of a mixture that sells for $8.95 per pound? 
Quantity Eq::: x + y = 15 lbs.
Value Eq:::::7.5x+10y= 8.95*15
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Multiply the Quantity eq. by 75:: 75x + 75y = 75*15
Multiply the Value eq. by 10::::: 75x + 100y= 89.5*15
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Subtract the 1st eq. from the 2nd and solve for "y":
25y = 14.5*15
y = 8.7 lbs (amt. of $10 coffee needed in the mixture)
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x = 15-8.7 = 6.3 lbs (amt. of $7.50 coffee needed in the mixture)
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Copy and complete the table below. (i am trying my best to copy the table...what is the difference between the cost per pound and the cost in dollars?) 
::::::::::::AMOUNT, COST PER POUND, COST DOLLARS are on the top (labels)
COFFEE 1::::..x.........7.5...............7.5x 
COFFEE 2::::..y..........10...............10x 
MIXTURE:::::x+y..........8.95.............8.9*15

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Cheers,
Stan H.
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