Question 341507
Find 3 consecutive integers in which the sum of the first two is 90 more than the last.
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1st: x
2nd: x+1
3rd: x+2
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Equation:
x + x+1 = x+2 + 90
2x+1 = x+92
x = 91
x+1 = 92
x+2 = 93
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Cheers,
Stan H.
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