Question 4935
{{{ 4y - 3/(6y) }}}

You can reduce the fraction by dividing out the 3 factor:
{{{(4y)/1 - 1/(2y) }}}


Next find a common denominator, which is 2y.  You must multiply the first fraction by {{{ (2y) /(2y) }}}

{{{ ((4y)/1 * (2y)/(2y)) - (1/ (2y) )}}}
{{{( 8y^2)/(2y) - 1/ (2y) }}}


Now subtract numerators, and place over the common denominator:
{{{(8y^2 - 1) /(2y) }}}


R^ 2 at SCC