Question 341194
 Find the measures of the angles of a triangle if the measure of one angle is twice the measure of a second angle and the third angle measures 3 times the second angle decreased by 12.
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Equations:
x + y + z = 180
x = 2y
z = 3y-12
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Substitute and solve for "y";
2y + y + 3y-12 = 180
6y = 192
y = 32 degrees
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x = 2y = 64 degrees
z = 3y-12 = 96-12 = 84 degrees
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Cheers,
Stan H.