Question 340964
if you go -315 degrees, you basically go clockwise and end up in quadrant I at 45 degrees, here {{{x=sqrt(2)/2}}} and {{{y=sqrt(2)/2}}}
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Cot(theta) = x/y
{{{cot(-315)=cot(45)=(sqrt(2)/2)/(sqrt(2)/2)=1}}}