Question 340943
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Absolutely correct.  The solution set is the empty set, *[tex \Large \ \ \empty]


If you solve the problem by ordinary methods you obtain the solution *[tex \Large x\ =\ -6].  However, that solution must be discarded because it causes two of the three denominators to go to zero.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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