Question 340849
There seems to be something wrong but here goes:

Let x=hundred's digit
Then 2x=ten's digit
And x+3=unit's digit

Sum of the number's digits:x+2x+x+3=4x+3
So our equation to solve is:
(100x+20x+x+3)/(4x+3)=22  multiply each side by 4x+3 and simplify
121x+3=88x+66 subtract 88x and 3 from each side
121x-88x+3-3=88x-88x+66-3  collect like terms
33x=63
x=1.909 which rounds off to 2
so x=2
2x=4
x+3=5

The number is 245
ck
245/11=22.2 which rounds off to 22

Another way to look at this problem:
Clearly the 100's digit cannot be greater than 4.  If it was, then the 10's digit would itself be a 2-digit number which is not allowed

So we only have 4 possibilities for the 100's digit:
if the 100's digit is 1
the 10's digit is 2 and the unit's digit is 4
the number would be 124
if the 100's digit is 2
the 10's digit is 4 and the units digit is 5
the number would be 245
if the 100's digit is 3
the 10's digit is 6 and the unit's digit is 6
the number would be 366
if the 100's digit is 4
the 10's digit is 8 and the unit's digit is 7
the number would be 487

The number 245, although not an exact solution, comes closer than any of the others

Hope this helps---ptaylor