Question 340747
{{{9(x-4)^2+1=0}}}
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{{{(x-4)^2=-1/9}}}
x-4=-+{{{sqrt(-1/9)}}}=-+{{{sqrt(-1*(1/9))}}}=-+{{{sqrt(-1)*sqrt(1/9)}}}=-+{{{i*sqrt(1/9)}}}
x-4=-+{{{i*sqrt(1)/sqrt(9)}}}=-+{{{i/3}}}
x=4-i/3 or x=4+i/3