<PRE><B>Question 340733</B>
let them meet at distance x miles from one end.( man walking)
the other man will ride 5-x 
speed of walking 3mph
speed of riding = 12 mph.
time taken walking = x/3
time taken riding = 5-x / 12
..
Since they start at the same time the time to meet is same.
x/3 = 5-x  /12
12x=3(5-x)
12x=15-3x
12x+3x= 15
15x = 15
x= 15/15
x=1 mile they meet at distance of 1 mile from the end where man starts walking.
distance = 1
speed = 3
time = distance /speed
time = 1  / 3 hours
= 20 minutes
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